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Q257.java
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83 lines (79 loc) · 2.15 KB
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/*
* @Author: Shawn Yang
* @Date: 2019-09-12 03:09:11
* @Last Modified by: Shawn Yang
* @Last Modified time: 2019-09-12 09:51:47
*/
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
/********************** So Slow Method ***************/
class Solution {
Stack<Integer> stack;
List<String> results;
public List<String> binaryTreePaths(TreeNode root) {
stack = new Stack<>();
results = new LinkedList<>();
if(root != null) {
dfs(root);
}
return results;
}
public void dfs(TreeNode root) {
if(root.left == null && root.right == null) {
stack.push(root.val);
addToResult();
stack.pop();
}
else if(root.left == null && root.right != null) {
stack.push(root.val);
dfs(root.right);
stack.pop();
}
else if(root.left != null && root.right == null) {
stack.push(root.val);
dfs(root.left);
stack.pop();
} else {
stack.push(root.val);
dfs(root.left);
dfs(root.right);
stack.pop();
}
}
public void addToResult() {
String result = "";
for(Integer num: stack) {
result += String.valueOf(num);
result += "->";
}
result = result.substring(0, result.length() - 2);
results.add(result);
}
}
/*************************More concise solution ************/
class Solution {
public void construct_paths(TreeNode root, String path, LinkedList<String> paths) {
if(root != null) {
path += String.valueOf(root.val);
if(root.left == null && root.right == null) {
paths.add(path);
} else {
path += "->";
construct_paths(root.left, path, paths);
construct_paths(root.right, path, paths);
}
}
}
public List<String> binaryTreePaths(TreeNode root) {
LinkedList<String> paths = new LinkedList();
construct_paths(root, "", paths);
return paths;
}
}